Opening a program using a batch file

Hi All,

I am trying to write a simple batch file to open a program located in my c:\Program Files directory and keep getting an error. I have typed:

START /DC:\Program Files\<Program Folder>\<Program Exe>

Could someone point out what I'm doing wrong. I'm running the batch file on a Windows XP PC.

Cheers

 

try:
CD C:\Program Files\<program folder>
<program name>.exe

 

I tried CD C:\Program Files\<Program Folder>\<Program Name> and it doesn't work. I get the following error:

The directory is invalid. Any other ideas? I'm going to try running a program from the root folder.

Cheers

 

You need to do these on two separate lines with a line return (enter) between them. The first line navigates to the directory (CD - Change Directory) and the second line tells the program to execute:

CD C:\Program Files\<Program Folder>\
Then enter
<Program Name>.exe

 

Thanks! In the end I did what you said and used START <Program.exe> on the second line.

 

Maybe I missed the START then, but at least you got it working. Great!

 

You should try quoting a path that has spaces in it.
Instead of
C:\Program Files\CamStudio\recorder.exe
That line errors
"C:\Program Files\CamStudio\recorder.exe"
This works fine.