how do i command an application to run on start up?

i want to add my bluetooth system tray icon to the system tray automaticly on start up. currently it is a short cut on my desk top and when i start it all it does is open in the system tray... i can see the target .exe... so how do i tell my computer to run that on each start up?

 

Right-click that icon on the desktop, and choose Copy.

Then ...

Right click the Start button > Explore > navigate to the Programs folder > open the Startup folder > right-click IN THE Startup FOLDER, and choose Paste.

You now have the action of that desktop icon taking place every time you boot.

Reboot and check it out. If the tray icon doesn't wind up where you want it, use a freeware startup delayer like Delayexec.

Delayexec is not on Major Geeks (yet), so get it here:

http://www.rjlsoftware.com/software/utility/delayexec/

(Now, if you want the action that occurs when you click the TRAY ICON to happen whenever you boot, put a shortcut to that exe in the Startup folder instead.)

 

thanks... i was trying to do that but didn't use explore... thanks alot...

cheers


z