weird cpp error

when I run this, it doesn't do what it's supposed to. It's an ascii space invaders game(my first game programming project). It's supposed to go left when you press a, and right when you press d.

Code:

#include <stdio.h>			// for printf
#include <conio.h>			// for getch
#include <string.h>
#include <iostream.h>



char espace_vaisseau[76];
char left_right;
int espace = 39;
int count;
int loop;

main ()
{
	strcpy(espace_vaisseau, "                                       ");		// graphics pour le vaisseau

	

	cout << "\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n";

	cout << "^W^" << espace_vaisseau ; // afficher vaisseau

for(loop = 0; loop < 4; loop + 0)       // infinite loop; while didn't work
	{
		if((left_right = getch()) == 'a')
		{
			espace--;
		}
		else if ((left_right = fetch()) == 'd')
		{
			espace++;
		}
		if (espace < 0)
		{
			espace++;
		}
		else if (espace > 76)
		{
			espace--;
		}

		for (count = 0; count <= espace; count++)
		{
			espace_vaisseau[count]=' ';
		}

		printf("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");

		printf("%s^W^", espace_vaisseau); // afficher vaisseau
	}

return (0);
}  

 

Your first else if statement has a call to fetch rather than getch to read the next character from the keyboard.

Also, you are mixing C calls (printf) with C++ syntax (cout <<).

What do you do with the while statement?

Does for (; ; ) not work as well?

 

sorry, fixed version:

Code:

#include <stdio.h>			// for printf
#include <conio.h>			// for getch
#include <string.h>
#include <iostream.h>



char espace_vaisseau[76];
char left_right;
int espace = 39;
int count;
int loop;

main ()
{
	strcpy(espace_vaisseau, "                                       ");		// graphics pour le vaisseau

	

	printf("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");

	printf("%s^W^", espace_vaisseau); // afficher vaisseau

for(;;)		// infinite loop
	{
		if((left_right = getch()) == 'a')
		{
			espace--;
		}
		else if ((left_right = getch()) == 'd')
		{
			espace++;
		}
		if (espace < 0)
		{
			espace++;
		}
		else if (espace > 76)
		{
			espace--;
		}

		for (count = 0; count <= espace; count++)
		{
			espace_vaisseau[count]=' ';
		}

		printf("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");

		printf("%s^W^", espace_vaisseau); // afficher vaisseau
	}

return (0);
} 

isn't there a 'edit post'?

 

got it! this is the corrected verision. 81 array elements instead of 77, and end of string character at end of string.

Code:

#include <stdio.h>			// for printf
#include <conio.h>			// for getch
#include <string.h>
#include <iostream.h>



char espace_vaisseau[81];
char left_right;
int espace = 39;
int count;
int loop;

main ()
{
	strcpy(espace_vaisseau, "                                       ");		// graphics pour le vaisseau

	

	printf("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");

	printf("%s^W^\0", espace_vaisseau); // afficher vaisseau

	for(;;)		// infinite loop
	{
		if((left_right = getch()) == 'a')
		{
			espace--;
		}
		else if ((left_right = getch()) == 'd')
		{
			espace++;
		}
		if (espace < 0)
		{
			espace++;
		}
		else if (espace > 76)
		{
			espace--;
		}

		for (count = 0; count <= espace; count++)
		{
			espace_vaisseau[count]=' ';
		}

		espace_vaisseau[count] = '\0';

		printf("\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n");

		printf("%s^W^", espace_vaisseau); // afficher vaisseau
	}

return (0);
} 

 

Yea, an infinite for loop can be constructed with

for(;
{
}

I believe any for loop which isn't completed properly defaults to an infinite one
but I may be wrong on that...
So
for(i=0 ; i<10 ; )
is also an infinite loop...