The Art of Ratios

Discussion in 'The Lounge' started by sibeer, Mar 13, 2005.

  1. sibeer

    sibeer MajorGeek

    This is a picture of the drive train in our living room that we use to raise the roof when it gets too hot in the summer........ok, nobodys buying that. This is a work of art, created by my buddy the mandolin builder. It doesn't do anything except annoy my mother when she's visiting. Assuming the largest gear to be "D", and the worm gear to be "A", calculate the following ratios.
    1. A : B
    2. A : C
    3. A : D
    It's actually very easy, so none of this waiting for GT to figure it out and then just agreeing with him!
     
  2. scorcer

    scorcer ajMro keGe

    ok, i wont wait for GT,,,

    I'll agree with him NOW :D
     
  3. G.T.

    G.T. R.I.P February 4, 2007. You will be missed.

    Pitch on the worm gear looks to be one tooth per revolution, so

    A:B = 1:13
    A:C = 1:17
    A:D = 1:28

    The odd intermediate gears don't really confuse things any, as each gear moves one tooth for each rotation of the worm gear.
     
  4. Strogg

    Strogg 5-Star Freakin' Geek

    my guess:

    1:13
    1:16
    1:29

    ok... well, i'm probably wrong, so i'm going to agree with gt as well:D
     
  5. jarcher

    jarcher I can't handle a title

    um . .no?

    cool art
    da^^n cool
     
  6. G.T.

    G.T. R.I.P February 4, 2007. You will be missed.

    Sheesh! I can't even count gear teeth before coffee.

    B has 12 teeth, and C has 15, or am I still cross-eyed? So

    A:B = 1:12
    A:C = 1:15
    A: D = 1:28
     
  7. jarcher

    jarcher I can't handle a title

    :)
    assuming that all cogs where complete
    I don't like to disagree with GT
    so I just left it as is

    but being that two (A and D) are incomplete gears

    A: can only move .25 a rotation correct?

    but lets assume that A is complete and D is as is?
    so
    A moves around fully once
    moving B 3 teeth
    moving c 2 teeth
    moving D 1 tooth

    hmmm. . .?
     
  8. G.T.

    G.T. R.I.P February 4, 2007. You will be missed.

    A seems to be the question mark. Draw a straight line across from one of the worm gear's "teeth", and you go from one tooth to one cavity, which would represent half of one rotation of the gear. This implies that one full revolution would move one full tooth, so one tooth per revolution.
     
  9. sibeer

    sibeer MajorGeek

    Glad to see you changed your original calculations GT. I had to recount the teeth myself to make sure I was correct. I held a straight edge across the diameter of gear D. so I figure if the entire gear existed then it would have thirty teeth. Looking at it on the screen, It's hard to tell how many teeth it would have. The worm gear has only one tooth therefore the A : D ratio is 30:1. The idler gears in between have no effect on the final ratio, and in this case don't even serve to change final direction. They're only there to look good.http://forums.majorgeeks.com/images/icons/icon7.gif
     
  10. G.T.

    G.T. R.I.P February 4, 2007. You will be missed.

    LOL. Whatever the actual count on D, we're working in the same direction. :)
     

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